Maxima & MinimaJEE Main

Critical points of a cubic — interactive Mathematics simulation for IIT-JEE.

Concept

At a smooth peak or valley of a curve the tangent is horizontal, so the derivative is zero. These are the critical points. The second derivative then tells them apart: concave-down (f<0f''<0) is a maximum, concave-up (f>0f''>0) is a minimum.

Key formula

f(x)=0    critical x;f(x)<0max,  f(x)>0minf'(x) = 0 \;\Rightarrow\; \text{critical } x; \quad f''(x)<0 \Rightarrow \max, \; f''(x)>0 \Rightarrow \min

Derivation

For a cubic f=ax3+bx2+cx+df = ax^3+bx^2+cx+d, the derivative f(x)=3ax2+2bx+cf'(x) = 3ax^2 + 2bx + c is a quadratic. Its discriminant decides how many turning points exist: two (distinct real roots), one inflection (repeated root), or none.

Evaluate f(x)=6ax+2bf''(x) = 6ax + 2b at each critical point to classify it. A cubic has at most one local max and one local min.

Scenarios to explore

  • Maxima & Minima — Critical points of a cubic by the second-derivative test.

Real-world applications

  • Optimisation: largest volume, least cost, shortest time.
  • Finding equilibrium points where potential energy is stationary.
  • Curve sketching for graph problems.

JEE exam tips

  • If ff' has no real roots, the cubic is monotonic — no turning points at all.
  • For closed intervals, the absolute extrema are among critical points and the two endpoints.

Common mistakes

  • Stopping at f(x)=0f'(x)=0 without classifying with ff'' or a sign chart.
  • Confusing a local extremum with the global one on a closed interval — check endpoints too.
  • Assuming f=0f''=0 always means an inflection (need a sign change).

Exam traps to avoid

  • A point with f=0f'=0 and f=0f''=0 may still be an extremum — fall back on the first-derivative sign test.
  • Turning points need ff''s discriminant >0> 0; tune cc to make them appear or vanish.