First-Order ODEJEE Main

Slope field & exponential solution — interactive Mathematics simulation for IIT-JEE.

Concept

A differential equation links a function to its own rate of change. The separable equation dydx=ky\frac{dy}{dx} = ky describes anything growing or decaying in proportion to itself — its solution is the exponential y=y0ekxy = y_0 e^{kx}. The slope field shows the direction every solution must follow.

Key formula

dydx=ky    y=y0ekx\frac{dy}{dx} = ky \;\Longrightarrow\; y = y_0\,e^{kx}

Derivation

Separate the variables: dyy=kdx\frac{dy}{y} = k\,dx. Integrating both sides gives lny=kx+C\ln|y| = kx + C.

Exponentiating, y=Aekxy = Ae^{kx}, and applying y(0)=y0y(0)=y_0 fixes A=y0A=y_0. The constant kk sets the doubling time (ln2/k\ln 2/k for growth) or half-life (ln2/k\ln 2/|k| for decay).

Scenarios to explore

  • First-Order ODE — Slope field and exponential solution of dy/dx = ky.

Real-world applications

  • Radioactive decay and population growth.
  • Newton's law of cooling.
  • RC and RL circuit charging/discharging.

JEE exam tips

  • Always separate variables first for dy/dx=f(x)g(y)dy/dx = f(x)g(y) equations.
  • Half-life =ln2/k= \ln 2/|k|; the solution never actually reaches zero.
  • A negative kk flips growth into decay; k=0k=0 gives a constant solution.

Common mistakes

  • Dropping the constant of integration CC before applying the initial condition.
  • Forgetting the modulus when integrating 1/y1/y.
  • Confusing the rate kk with the solution value.

Exam traps to avoid

  • ekxe^{kx} is never zero — exponential decay approaches but never hits the axis.
  • The slope field's segments depend on yy only here, so they are horizontal where y=0y=0.