Colligative PropertiesJEE Main

Freezing-point depression & boiling-point elevation — interactive Chemistry simulation for IIT-JEE.

Concept

Colligative properties depend only on the number of dissolved particles, not their identity. Dissolving a solute lowers the freezing point and raises the boiling point — which is why salt melts ice and antifreeze protects engines.

Key formula

ΔTf=iKfm,ΔTb=iKbm\Delta T_f = i\,K_f\,m, \qquad \Delta T_b = i\,K_b\,m

Derivation

A solute lowers the solvent's vapour pressure (Raoult's law), shifting the phase boundaries: the liquid must be cooled further to freeze and heated further to boil.

The shifts scale with molality mm and the van't Hoff factor ii — the number of particles each formula unit releases (NaCl → 2 ions, so i=2i = 2). For water, Kf=1.86K_f = 1.86 and Kb=0.512K_b = 0.512 K·kg·mol⁻¹.

Scenarios to explore

  • Colligative Properties — Freezing-point depression & boiling-point elevation.

Real-world applications

  • De-icing roads and antifreeze in radiators.
  • Determining molar masses of unknown solutes.
  • Osmosis in cells and desalination.

JEE exam tips

  • Ranking effect: more particles (higher i×mi \times m) means larger ΔT\Delta T.
  • For weak electrolytes, i=1+(n1)αi = 1 + (n-1)\alpha links to the degree of dissociation.

Common mistakes

  • Forgetting the van't Hoff factor for ionic solutes.
  • Using molarity instead of molality.
  • Sign error — freezing point goes down, boiling point goes up.

Exam traps to avoid

  • Equal molality of NaCl and glucose are not equal in effect — NaCl's i=2i=2 doubles it.
  • Colligative properties ignore the solute's chemical nature entirely.