Acid–Base TitrationJEE Main

pH curve and the equivalence point — interactive Chemistry simulation for IIT-JEE.

Concept

A titration tracks pH as base is added to acid. The curve stays gentle, then leaps at the equivalence point — where moles of base exactly neutralise the acid. A weak acid adds a flat buffer region before the jump.

Key formula

nacid=nbase at equivalence,pH=pKa+log[A][HA]n_{acid} = n_{base} \text{ at equivalence}, \quad \text{pH} = \text{p}K_a + \log\frac{[A^-]}{[HA]}

Derivation

Before equivalence the leftover strong acid sets [H+]=nacidnbaseVtotal[H^+] = \dfrac{n_{acid}-n_{base}}{V_{total}}. For a weak acid the buffer region follows Henderson–Hasselbalch, with pH = pKaK_a at the half-equivalence point.

At equivalence a strong–strong titration gives pH 7; a weak acid leaves its conjugate base, which hydrolyses to give pH > 7. Past equivalence, excess OHOH^- dominates.

Scenarios to explore

  • Acid–Base Titration — pH curve and the equivalence point.

Real-world applications

  • Determining unknown acid concentrations in the lab.
  • Choosing indicators (matched to the equivalence pH).
  • Quality control of foods and pharmaceuticals.

JEE exam tips

  • Half-equivalence (Vb = Veq/2) of a weak acid gives pH = pKaK_a directly.
  • Equivalence volume is Veq=CaVa/CbV_{eq} = C_aV_a/C_b regardless of strength.

Common mistakes

  • Assuming every equivalence point is at pH 7 — only strong–strong is.
  • Forgetting the total volume increases as titrant is added.
  • Mislabelling the half-equivalence point — that is where pH = pKaK_a.

Exam traps to avoid

  • A weak-acid equivalence point is basic (pH > 7) due to conjugate-base hydrolysis.
  • The steep region is narrow for strong acids, broader/lower for weak ones.