Sound Intensity & DecibelsJEE Main

Inverse-square spreading and the dB scale — interactive Physics simulation for IIT-JEE.

Concept

A point source spreads its power over ever-larger spheres, so intensity falls as 1/r21/r^2. Ears sense ratios, not differences — hence the logarithmic decibel scale: every ×10 in intensity is +10 dB, every doubling of distance is −6 dB.

Key formula

I=P4πr2,β=10log10II0,I0=1012W/m2I = \frac{P}{4\pi r^2}, \qquad \beta = 10\log_{10}\frac{I}{I_0}, \qquad I_0 = 10^{-12}\,\text{W/m}^2

Derivation

Energy conservation: power P crosses every sphere of area 4πr24\pi r^2, so I=P/4πr2I = P/4\pi r^2.

Doubling r: II/4I \to I/4, Δβ=10log(1/4)6\Delta\beta = 10\log(1/4) \approx -6\,dB. Two equal sources: I2II \to 2I, +3+3\,dB — 'twice the speakers' is barely louder.

Scenarios to explore

  • Decibel Scale — Inverse-square intensity and the logarithmic dB ladder.

Real-world applications

  • Concert & PA system design (line arrays fight the 1/r² loss).
  • Workplace noise limits (85 dB for 8 h).
  • Sonar & ultrasound ranging power budgets.

JEE exam tips

  • +10 dB = ×10 intensity, +3 dB = ×2, +6 dB = ×4 — arithmetic in your head.
  • n equal sources: β = β₁ + 10 log n.
  • I ∝ (amplitude)² ⇒ dB difference = 20 log(A₂/A₁).

Common mistakes

  • Adding decibels directly for two sources — add INTENSITIES, then convert.
  • −3 dB for doubling distance (that's for halving intensity; distance doubling gives −6 dB).
  • Using amplitude ratios with the 10log formula (amplitude uses 20log).

Exam traps to avoid

  • 0 dB is not silence — it's the hearing threshold I₀.
  • dB is dimensionless; intensity carries the W/m² units.