Binomial DistributionJEE Main

n trials, probability p — interactive Mathematics simulation for IIT-JEE.

Concept

The binomial distribution counts the number of successes in nn independent yes/no trials, each succeeding with probability pp. It governs anything from coin tosses to defect counts, and its shape shifts from skewed to symmetric as pp moves toward 12\tfrac12.

Key formula

P(X=k)=(nk)pk(1p)nk,μ=np,σ2=np(1p)P(X=k) = \binom{n}{k}p^k(1-p)^{n-k}, \quad \mu = np, \quad \sigma^2 = np(1-p)

Derivation

Each specific sequence with kk successes and nkn-k failures has probability pk(1p)nkp^k(1-p)^{n-k}.

There are (nk)\binom{n}{k} such sequences (the ways to choose which trials succeed), so multiply to get the PMF.

Writing XX as a sum of nn independent Bernoulli variables gives mean npnp and, by independence, variance np(1p)np(1-p).

Scenarios to explore

  • Binomial Distribution — n trials, probability p — the binomial PMF.

Real-world applications

  • Quality control — number of defective items in a batch.
  • Polling and survey sampling.
  • Genetics — inheritance counts across offspring.

JEE exam tips

  • Mean is always npnp; variance np(1p)np(1-p) is largest at p=12p = \tfrac12.
  • For large nn the binomial approaches a normal with the same mean and variance.

Common mistakes

  • Forgetting the binomial coefficient (nk)\binom{n}{k}.
  • Using the binomial when trials are not independent or pp is not constant.
  • Confusing variance np(1p)np(1-p) with the standard deviation.

Exam traps to avoid

  • Variance np(1p)np(1-p) is always less than the mean npnp (since 1p<11-p<1).
  • Mode is around npnp, but use (n+1)p\lfloor (n+1)p\rfloor for the exact most-likely value.